b/b-2+4/b+2=8/b^2-4

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Solution for b/b-2+4/b+2=8/b^2-4 equation: 


D( b )

b^2 = 0

b = 0

b^2 = 0

b^2 = 0

1*b^2 = 0 // : 1

b^2 = 0

b = 0

b = 0

b = 0

b in (-oo:0) U (0:+oo)

4/b+b/b-2+2 = 8/(b^2)-4 // - 8/(b^2)-4

4/b-(8/(b^2))+b/b-2+2+4 = 0

4/b-8*b^-2+b/b-2+2+4 = 0

4*b^-1-8*b^-2+5 = 0

t_1 = b^-1

4*t_1^1-8*t_1^2+5 = 0

4*t_1-8*t_1^2+5 = 0

DELTA = 4^2-(-8*4*5)

DELTA = 176

DELTA > 0

t_1 = (176^(1/2)-4)/(-8*2) or t_1 = (-176^(1/2)-4)/(-8*2)

t_1 = (4*11^(1/2)-4)/(-16) or t_1 = (-4*11^(1/2)-4)/(-16)

t_1 = (4*11^(1/2)-4)/(-16)

b^-1-((4*11^(1/2)-4)/(-16)) = 0

1*b^-1 = (4*11^(1/2)-4)/(-16) // : 1

b^-1 = (4*11^(1/2)-4)/(-16)

-1 < 0

1/(b^1) = (4*11^(1/2)-4)/(-16) // * b^1

1 = ((4*11^(1/2)-4)/(-16))*b^1 // : (4*11^(1/2)-4)/(-16)

-16*(4*11^(1/2)-4)^-1 = b^1

b = -16*(4*11^(1/2)-4)^-1

t_1 = (-4*11^(1/2)-4)/(-16)

b^-1-((-4*11^(1/2)-4)/(-16)) = 0

1*b^-1 = (-4*11^(1/2)-4)/(-16) // : 1

b^-1 = (-4*11^(1/2)-4)/(-16)

-1 < 0

1/(b^1) = (-4*11^(1/2)-4)/(-16) // * b^1

1 = ((-4*11^(1/2)-4)/(-16))*b^1 // : (-4*11^(1/2)-4)/(-16)

-16*(-4*11^(1/2)-4)^-1 = b^1

b = -16*(-4*11^(1/2)-4)^-1

b in { -16*(4*11^(1/2)-4)^-1, -16*(-4*11^(1/2)-4)^-1 }

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